What are the solutions to the equation 6x^2+4x-8=0 ?

The solutions to the equation 6x^2+4x-8=0 are x=(-1+sqrt(13))/3 ,x=-(1+sqrt(13))/3

Find the zeros of 6x^2+4x-8=0

The zeros of 6x^2+4x-8=0 are x=(-1+sqrt(13))/3 ,x=-(1+sqrt(13))/3

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6 x^{2} + 4 x - 8 = 0

x = \frac{- 1 + 13}{3}, x = - \frac{1 + 13}{3}

Decimal Notation

x = 0.86851 \dots, x = - 1.53518 \dots

Solution steps

6 x^{2} + 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 8 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 8) = 413

x_{1, 2} = \frac{- 4 \pm 4 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 4 13}{2 \cdot 6}, x_{2} = \frac{- 4 - 4 13}{2 \cdot 6}

x = \frac{- 4 + 4 13}{2 \cdot 6} : \frac{- 1 + 13}{3}

x = \frac{- 4 - 4 13}{2 \cdot 6} : - \frac{1 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{3}, x = - \frac{1 + 13}{3}

- \frac{1}{16} x^{2} + 6 x + 3 = 0

x^{2} + 8 x - 55 = 10

4 z^{2} - 8 z + 5 = 2

\frac{1}{x + h + 1} - \frac{1}{x + 1}

lo g_{3} (64)

What are the solutions to the equation 6x^2+4x-8=0 ?
The solutions to the equation 6x^2+4x-8=0 are x=(-1+sqrt(13))/3 ,x=-(1+sqrt(13))/3
Find the zeros of 6x^2+4x-8=0
The zeros of 6x^2+4x-8=0 are x=(-1+sqrt(13))/3 ,x=-(1+sqrt(13))/3