What is the answer to 2^{2x-1}= 1/(5^{2x-1)} ?

The answer to 2^{2x-1}= 1/(5^{2x-1)} is x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2x-1}= 1/(5^{2x-1)}

2^{2 x - 1} = \frac{1}{5 ^{2 x - 1}}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

2^{2 x - 1} = \frac{1}{5 ^{2 x - 1}}

Apply exponent rules

(2 x - 1) ln (2) = (- 2 x + 1) ln (5)

Solve

(2 x - 1) ln (2) = (- 2 x + 1) ln (5) : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

1 5^{- 9 x} = 5

4^{3 x - 4} = 1024

n, 9 + 3^{n + 2} = m

5^{x - 2} = 2

5^{x - 2} = 9

What is the answer to 2^{2x-1}= 1/(5^{2x-1)} ?
The answer to 2^{2x-1}= 1/(5^{2x-1)} is x= 1/2
Solve for x: 2^{2x-1}= 1/(5^{2x-1)}
The solution is x= 1/2