What is the answer to solvefor n,9+3^{n+2}=m ?

The answer to solvefor n,9+3^{n+2}=m is n=(ln(m-9))/(ln(3))-2

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solvefor n,9+3^{n+2}=m

solve for

n, 9 + 3^{n + 2} = m

n = \frac{ln ( m - 9 )}{ln ( 3 )} - 2

Solution steps

9 + 3^{n + 2} = m

Move

9

to the right side

3^{n + 2} = m - 9

Apply exponent rules

(n + 2) ln (3) = ln (m - 9)

Solve

(n + 2) ln (3) = ln (m - 9) : n = \frac{ln ( m - 9 )}{ln ( 3 )} - 2

n = \frac{ln ( m - 9 )}{ln ( 3 )} - 2

5^{x - 2} = 2

5^{x - 2} = 9

4000 = 2^{x}

3 \cdot 2^{3 x} = 7 \cdot 3^{3 x - 2}

(3^{2 x + 1} + 9) = (3^{x + 3} + 3^{x})

What is the answer to solvefor n,9+3^{n+2}=m ?
The answer to solvefor n,9+3^{n+2}=m is n=(ln(m-9))/(ln(3))-2