What is the answer to 4^{x+4}=5^x ?

The answer to 4^{x+4}=5^x is x=(8ln(2))/(ln(5)-2ln(2))

Solve for x: 4^{x+4}=5^x

The solution is x=(8ln(2))/(ln(5)-2ln(2))

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4^{x + 4} = 5^{x}

x = \frac{8 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

Solution steps

4^{x + 4} = 5^{x}

Apply exponent rules

(x + 4) ln (4) = x ln (5)

Solve

(x + 4) ln (4) = x ln (5) : x = \frac{8 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

x = \frac{8 ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

8 x = 3. 2^{6 x}

1 0^{x - 1} = 8 \cdot 3^{x}

x = e^{1 - x}

800 = 60 (1.25)^{x}

21 6^{2 x - 3} = 3 6^{- x + 7}

What is the answer to 4^{x+4}=5^x ?
The answer to 4^{x+4}=5^x is x=(8ln(2))/(ln(5)-2ln(2))
Solve for x: 4^{x+4}=5^x
The solution is x=(8ln(2))/(ln(5)-2ln(2))