What is the answer to 993=10^{((1.25-m+5))/5} ?

The answer to 993=10^{((1.25-m+5))/5} is m=-(5ln(993))/(ln(10))+6.25

Solve for m: 993=10^{((1.25-m+5))/5}

The solution is m=-(5ln(993))/(ln(10))+6.25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

993 = 1 0^{\frac{( 1.25 - m + 5 )}{5}}

m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

Solution steps

993 = 1 0^{\frac{( 1.25 - m + 5 )}{5}}

Apply exponent rules

ln (993) = \frac{1.25 - m + 5}{5} ln (10)

Solve

ln (993) = \frac{1.25 - m + 5}{5} ln (10) : m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

m = - \frac{5 ln ( 993 )}{ln ( 10 )} + 6.25

2 = 1.0 6^{n}

5 e^{x} + 48 e^{- x} = 46

t, 45 x 1.07 1^{t} = 122

1 6^{x - 3} = 2^{x - 6}

n = 1. 2^{n}

What is the answer to 993=10^{((1.25-m+5))/5} ?
The answer to 993=10^{((1.25-m+5))/5} is m=-(5ln(993))/(ln(10))+6.25
Solve for m: 993=10^{((1.25-m+5))/5}
The solution is m=-(5ln(993))/(ln(10))+6.25