What is the answer to 8^{x+7}=9^x ?

The answer to 8^{x+7}=9^x is x=(21ln(2))/(2ln(3)-3ln(2))

Solve for x: 8^{x+7}=9^x

The solution is x=(21ln(2))/(2ln(3)-3ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8^{x + 7} = 9^{x}

x = \frac{21 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

Decimal Notation

x = 123.58393 \dots

Solution steps

8^{x + 7} = 9^{x}

Apply exponent rules

(x + 7) ln (8) = x ln (9)

Solve

(x + 7) ln (8) = x ln (9) : x = \frac{21 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

x = \frac{21 ln ( 2 )}{2 ln ( 3 ) - 3 ln ( 2 )}

(x - 3)^{2 x - 1} = (x - 3)^{x + 1}

1 0^{c} = 10000000

1.09 2^{- n} = 0.5613

3^{x} + 3^{x + 2} = 810

\frac{5 ^{x}}{5} = 5^{2}

What is the answer to 8^{x+7}=9^x ?
The answer to 8^{x+7}=9^x is x=(21ln(2))/(2ln(3)-3ln(2))
Solve for x: 8^{x+7}=9^x
The solution is x=(21ln(2))/(2ln(3)-3ln(2))