What is the answer to (x-3)^{2x-1}=(x-3)^{x+1} ?

The answer to (x-3)^{2x-1}=(x-3)^{x+1} is x=4

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(x-3)^{2x-1}=(x-3)^{x+1}

(x - 3)^{2 x - 1} = (x - 3)^{x + 1}

x = 4

Solution steps

(x - 3)^{2 x - 1} = (x - 3)^{x + 1}

Apply exponent rules

(2 x - 1) ln (x - 3) = (x + 1) ln (x - 3)

Solve

(2 x - 1) ln (x - 3) = (x + 1) ln (x - 3) : x = 4

x = 4

1 0^{c} = 10000000

1.09 2^{- n} = 0.5613

3^{x} + 3^{x + 2} = 810

\frac{5 ^{x}}{5} = 5^{2}

3^{2 t - 2} = 7^{t + 2}

What is the answer to (x-3)^{2x-1}=(x-3)^{x+1} ?
The answer to (x-3)^{2x-1}=(x-3)^{x+1} is x=4
Solve for x: (x-3)^{2x-1}=(x-3)^{x+1}
The solution is x=4