What is the answer to 3^{x+1}+4=8 ?

The answer to 3^{x+1}+4=8 is x=(2ln(2))/(ln(3))-1

Solve for x: 3^{x+1}+4=8

The solution is x=(2ln(2))/(ln(3))-1

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3^{x + 1} + 4 = 8

x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

Decimal Notation

x = 0.26185 \dots

Solution steps

3^{x + 1} + 4 = 8

Move

4

to the right side

3^{x + 1} = 4

Apply exponent rules

(x + 1) ln (3) = ln (4)

Solve

(x + 1) ln (3) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

x = \frac{2 ln ( 2 )}{ln ( 3 )} - 1

e^{2} x - 4 e^{x} - 5 = 0

n, 4^{n + 1} = 8^{n - 2}

2^{2 x + 11} = 3^{x - 5}

(\frac{2}{5})^{x} = \frac{4}{25}

(x - 6)^{x^{2} - 5} = (x - 6)^{2 x + 3}

What is the answer to 3^{x+1}+4=8 ?
The answer to 3^{x+1}+4=8 is x=(2ln(2))/(ln(3))-1
Solve for x: 3^{x+1}+4=8
The solution is x=(2ln(2))/(ln(3))-1