What is the answer to 2^{20x+10}=32^{3x+6} ?

The answer to 2^{20x+10}=32^{3x+6} is x=4

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2^{20x+10}=32^{3x+6}

2^{20 x + 10} = 3 2^{3 x + 6}

x = 4

Solution steps

2^{20 x + 10} = 3 2^{3 x + 6}

Apply exponent rules

20 x + 10 = 5 (3 x + 6)

Solve

20 x + 10 = 5 (3 x + 6) : x = 4

x = 4

(0.5)^{- 25 6^{4^{x}}} = 4

5^{3 x + 2} = 1 1^{7 x - 2}

\frac{4 ^{x - 1}}{2 ^{x + 2}} = 256

2 7^{- x - 1} = 81

e^{- \frac{1}{2} x^{2}} = 0

What is the answer to 2^{20x+10}=32^{3x+6} ?
The answer to 2^{20x+10}=32^{3x+6} is x=4
Solve for x: 2^{20x+10}=32^{3x+6}
The solution is x=4