What is the answer to 7^{x+4}=8^x ?

The answer to 7^{x+4}=8^x is x=(4ln(7))/(3ln(2)-ln(7))

Solve for x: 7^{x+4}=8^x

The solution is x=(4ln(7))/(3ln(2)-ln(7))

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7^{x + 4} = 8^{x}

x = \frac{4 ln ( 7 )}{3 ln ( 2 ) - ln ( 7 )}

Decimal Notation

x = 58.29071 \dots

Solution steps

7^{x + 4} = 8^{x}

Apply exponent rules

(x + 4) ln (7) = x ln (8)

Solve

(x + 4) ln (7) = x ln (8) : x = \frac{4 ln ( 7 )}{3 ln ( 2 ) - ln ( 7 )}

x = \frac{4 ln ( 7 )}{3 ln ( 2 ) - ln ( 7 )}

\frac{1}{3 e ^{2 - 3 x} + 3} = 7

7^{3 x^{2}} = 4 9^{6 x + 2}

9^{x} - 4 = 3^{x + 1}

e^{x} + 6 \cdot e^{- x} = 5

100 - 98 y + 980 (1 - e^{- 0.1 y}) = 0

What is the answer to 7^{x+4}=8^x ?
The answer to 7^{x+4}=8^x is x=(4ln(7))/(3ln(2)-ln(7))
Solve for x: 7^{x+4}=8^x
The solution is x=(4ln(7))/(3ln(2)-ln(7))