What is the answer to x^{log_{3}(x)+1}=9 ?

The answer to x^{log_{3}(x)+1}=9 is x=3,x= 1/9

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x^{log_{3}(x)+1}=9

x^{l o g_{3} (x) + 1} = 9

x = 3, x = \frac{1}{9}

Solution steps

x^{l o g_{3} (x) + 1} = 9

Apply exponent rules

(lo g_{3} (x) + 1) ln (x) = ln (9)

Solve

(lo g_{3} (x) + 1) ln (x) = ln (9) : x = 3, x = \frac{1}{9}

x = 3, x = \frac{1}{9}

Verify Solutions:

x = 3

True

, x = \frac{1}{9}

True

The solutions are

x = 3, x = \frac{1}{9}

3^{(x - 1)} + 3^{x} = 4

0. 5^{x} = \frac{1}{16}

3^{(x + 2)} = 7

2^{3 x + 1} = 2^{3}

7^{x + 2} = 410

What is the answer to x^{log_{3}(x)+1}=9 ?
The answer to x^{log_{3}(x)+1}=9 is x=3,x= 1/9
Solve for x: x^{log_{3}(x)+1}=9
The solution is x=3,x= 1/9