What is the answer to 350=400*(1-e^{-0.15t}) ?

The answer to 350=400*(1-e^{-0.15t}) is t=(3ln(2))/(0.15)

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350=400*(1-e^{-0.15t})

350 = 400 \cdot (1 - e^{- 0.15 t})

t = \frac{3 ln ( 2 )}{0.15}

Solution steps

350 = 400 (1 - e^{- 0.15 t})

Switch sides

400 (1 - e^{- 0.15 t}) = 350

Divide both sides by

400

1 - e^{- 0.15 t} = \frac{7}{8}

Move

1

to the right side

- e^{- 0.15 t} = - \frac{1}{8}

Divide both sides by

- 1

e^{- 0.15 t} = \frac{1}{8}

Apply exponent rules

- 0.15 t = ln (\frac{1}{8})

Solve

- 0.15 t = ln (\frac{1}{8}) : t = \frac{3 ln ( 2 )}{0.15}

t = \frac{3 ln ( 2 )}{0.15}

9^{0.5 m} \cdot 9^{2 m} = 9^{2.5 m}

(4^{x - 1})^{2} - 10 (4^{x - 1}) + 16 = 0

n, x^{n} = ln (x + 1)

3^{- 5 x + 2} = (\frac{1}{9})^{x + 2}

2 + x = 2^{x}

What is the answer to 350=400*(1-e^{-0.15t}) ?
The answer to 350=400*(1-e^{-0.15t}) is t=(3ln(2))/(0.15)