What is the answer to 1/(2^{x+4)}=sqrt(8) ?

The answer to 1/(2^{x+4)}=sqrt(8) is x=-11/2

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1/(2^{x+4)}=sqrt(8)

\frac{1}{2 ^{x + 4}} = 8

x = - \frac{11}{2}

Solution steps

\frac{1}{2 ^{x + 4}} = 8

Apply exponent rules

- x - 4 = \frac{3}{2}

Solve

- x - 4 = \frac{3}{2} : x = - \frac{11}{2}

x = - \frac{11}{2}

Verify Solutions:

x = - \frac{11}{2}

True

The solution is

x = - \frac{11}{2}

2 = 1.0 2^{x}

2 5^{x} \cdot 5^{x^{2}} = 62 5^{2}

2^{4 x} = 256

y, (6 x)^{y} = 3 d + 4

- 6^{2 x} + 5 = - 18.5

What is the answer to 1/(2^{x+4)}=sqrt(8) ?
The answer to 1/(2^{x+4)}=sqrt(8) is x=-11/2
Solve for x: 1/(2^{x+4)}=sqrt(8)
The solution is x=-11/2