What is the answer to 5^{x+3}=7^{4-3x} ?

The answer to 5^{x+3}=7^{4-3x} is x=(4ln(7)-3ln(5))/(ln(1715))

Solve for x: 5^{x+3}=7^{4-3x}

The solution is x=(4ln(7)-3ln(5))/(ln(1715))

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5^{x + 3} = 7^{4 - 3 x}

x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

Decimal Notation

x = 0.39683 \dots

Solution steps

5^{x + 3} = 7^{4 - 3 x}

Apply exponent rules

(x + 3) ln (5) = (4 - 3 x) ln (7)

Solve

(x + 3) ln (5) = (4 - 3 x) ln (7) : x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

x = \frac{4 ln ( 7 ) - 3 ln ( 5 )}{ln ( 1715 )}

2 7^{x - 1} = 9

3^{2 x - 3} \cdot 9 = 1

12 = 21 e^{20 x}

12000 = 1520 \cdot 1.0 4^{x}

3^{2 x + 1} = 5 (3^{x}) + 2

What is the answer to 5^{x+3}=7^{4-3x} ?
The answer to 5^{x+3}=7^{4-3x} is x=(4ln(7)-3ln(5))/(ln(1715))
Solve for x: 5^{x+3}=7^{4-3x}
The solution is x=(4ln(7)-3ln(5))/(ln(1715))