What is the answer to 64^{-15x-27}=8^{3x^2-3x} ?

The answer to 64^{-15x-27}=8^{3x^2-3x} is x=-3,x=-6

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64^{-15x-27}=8^{3x^2-3x}

6 4^{- 15 x - 27} = 8^{3 x^{2} - 3 x}

x = - 3, x = - 6

Solution steps

6 4^{- 15 x - 27} = 8^{3 x^{2} - 3 x}

Apply exponent rules

2 (- 15 x - 27) = 3 x^{2} - 3 x

Solve

2 (- 15 x - 27) = 3 x^{2} - 3 x : x = - 3, x = - 6

x = - 3, x = - 6

1 0^{x} = 29

\frac{1}{729} = 3^{x}

- 3^{x} - 9 (3^{- x}) + 10 = 0

8^{x} - 8^{- x} = 8

2^{2 x + 1} 0. 4^{3 x + 1} = 8^{x - 1}

What is the answer to 64^{-15x-27}=8^{3x^2-3x} ?
The answer to 64^{-15x-27}=8^{3x^2-3x} is x=-3,x=-6
Solve for x: 64^{-15x-27}=8^{3x^2-3x}
The solution is x=-3,x=-6