What is the answer to 10^x=29 ?

The answer to 10^x=29 is x=(ln(29))/(ln(10))

The solution is x=(ln(29))/(ln(10))

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10^x=29

1 0^{x} = 29

x = \frac{ln ( 29 )}{ln ( 10 )}

Solution steps

1 0^{x} = 29

Apply exponent rules

x ln (10) = ln (29)

Solve

x ln (10) = ln (29) : x = \frac{ln ( 29 )}{ln ( 10 )}

x = \frac{ln ( 29 )}{ln ( 10 )}

\frac{1}{729} = 3^{x}

- 3^{x} - 9 (3^{- x}) + 10 = 0

8^{x} - 8^{- x} = 8

2^{2 x + 1} 0. 4^{3 x + 1} = 8^{x - 1}

1 0^{2 x} = 4