What is the answer to 10^{2x}=4 ?

The answer to 10^{2x}=4 is x=(ln(2))/(ln(10))

Solve for x: 10^{2x}=4

The solution is x=(ln(2))/(ln(10))

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1 0^{2 x} = 4

x = \frac{ln ( 2 )}{ln ( 10 )}

Decimal Notation

x = 0.30102 \dots

Solution steps

1 0^{2 x} = 4

Apply exponent rules

2 x ln (10) = ln (4)

Solve

2 x ln (10) = ln (4) : x = \frac{ln ( 2 )}{ln ( 10 )}

x = \frac{ln ( 2 )}{ln ( 10 )}

1 0^{2 x} = 5

1 0^{2 x} = 8

9^{x + 1} = 2 7^{5 x - 5}

190 = 70 + 130 (\frac{13}{12})^{- t}

2 7^{x - 1} = 3^{x + 5}