What is the answer to 9^{x+1}=27^{5x-5} ?

The answer to 9^{x+1}=27^{5x-5} is x= 17/13

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9^{x+1}=27^{5x-5}

9^{x + 1} = 2 7^{5 x - 5}

x = \frac{17}{13}

Decimal Notation

x = 1.30769 \dots

Solution steps

9^{x + 1} = 2 7^{5 x - 5}

Apply exponent rules

2 (x + 1) = 3 (5 x - 5)

Solve

2 (x + 1) = 3 (5 x - 5) : x = \frac{17}{13}

x = \frac{17}{13}

190 = 70 + 130 (\frac{13}{12})^{- t}

2 7^{x - 1} = 3^{x + 5}

25000 = 50000 (0.9)^{x - 1}

5^{4 x + 2} = 7^{x + 5}

2^{2 x} + 2^{x + 2} = 32

What is the answer to 9^{x+1}=27^{5x-5} ?
The answer to 9^{x+1}=27^{5x-5} is x= 17/13
Solve for x: 9^{x+1}=27^{5x-5}
The solution is x= 17/13