What is the answer to 25000=50000(0.9)^{x-1} ?

The answer to 25000=50000(0.9)^{x-1} is x=-(ln(2))/(ln(0.9))+1

Solve for x: 25000=50000(0.9)^{x-1}

The solution is x=-(ln(2))/(ln(0.9))+1

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25000 = 50000 (0.9)^{x - 1}

x = - \frac{ln ( 2 )}{ln ( 0.9 )} + 1

Solution steps

25000 = 50000 (0.9)^{x - 1}

Switch sides

50000 \cdot 0. 9^{x - 1} = 25000

Divide both sides by

50000

0. 9^{x - 1} = \frac{1}{2}

Apply exponent rules

(x - 1) ln (0.9) = ln (\frac{1}{2})

Solve

(x - 1) ln (0.9) = ln (\frac{1}{2}) : x = - \frac{ln ( 2 )}{ln ( 0.9 )} + 1

x = - \frac{ln ( 2 )}{ln ( 0.9 )} + 1

5^{4 x + 2} = 7^{x + 5}

2^{2 x} + 2^{x + 2} = 32

243 = 3^{\frac{m}{10}}

9^{x} - 16 \cdot 3^{x} + 27 = 0

3 e^{x} - x e^{x} = 0

What is the answer to 25000=50000(0.9)^{x-1} ?
The answer to 25000=50000(0.9)^{x-1} is x=-(ln(2))/(ln(0.9))+1
Solve for x: 25000=50000(0.9)^{x-1}
The solution is x=-(ln(2))/(ln(0.9))+1