What is the answer to 2500=2000(1.04)^x ?

The answer to 2500=2000(1.04)^x is x=(ln(5/4))/(ln(1.04))

Solve for x: 2500=2000(1.04)^x

The solution is x=(ln(5/4))/(ln(1.04))

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2500 = 2000 (1.04)^{x}

x = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

Solution steps

2500 = 2000 (1.04)^{x}

Switch sides

2000 \cdot 1.0 4^{x} = 2500

Divide both sides by

2000

1.0 4^{x} = \frac{5}{4}

Apply exponent rules

x ln (1.04) = ln (\frac{5}{4})

Solve

x ln (1.04) = ln (\frac{5}{4}) : x = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

x = \frac{ln ( \frac{5}{4} )}{ln ( 1.04 )}

lo g_{10} (3^{x}) = 81

1 5^{- 3 y} = 8

1 5^{- 3 y} = 9

y, z = x e^{x^{2} y}

lo g_{10} (10 0^{x}) = 70

What is the answer to 2500=2000(1.04)^x ?
The answer to 2500=2000(1.04)^x is x=(ln(5/4))/(ln(1.04))
Solve for x: 2500=2000(1.04)^x
The solution is x=(ln(5/4))/(ln(1.04))