What is the answer to log_{10}(100^x)=35 ?

The answer to log_{10}(100^x)=35 is x= 35/2

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log_{10}(100^x)=35

lo g_{10} (10 0^{x}) = 35

x = \frac{35}{2}

Decimal Notation

x = 17.5

Solution steps

lo g_{10} (10 0^{x}) = 35

Rewrite the equation with

10 0^{x} = u

lo g_{10} (u) = 35

Solve

lo g_{10} (u) = 35 : u = 1 0^{35}

u = 1 0^{35}

Substitute back

u = 10 0^{x},

solve for

x

Solve

10 0^{x} = 1 0^{35} : x = \frac{35}{2}

x = \frac{35}{2}

3 = 60 (2 - 60) e^{- 0.001 x}

3^{x + 5} = 7

5^{x} + 5^{x + 1} + 5^{x + 2} = 155

e^{x} + e^{- x} = 7.4533

x^{x} = 625

What is the answer to log_{10}(100^x)=35 ?
The answer to log_{10}(100^x)=35 is x= 35/2
Solve for x: log_{10}(100^x)=35
The solution is x= 35/2