What is the answer to 10^{2-2x}=2*10^{-x} ?

The answer to 10^{2-2x}=2*10^{-x} is x=(ln(50))/(ln(10))

Solve for x: 10^{2-2x}=2*10^{-x}

The solution is x=(ln(50))/(ln(10))

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1 0^{2 - 2 x} = 2 \cdot 1 0^{- x}

x = \frac{ln ( 50 )}{ln ( 10 )}

Solution steps

1 0^{2 - 2 x} = 2 \cdot 1 0^{- x}

Apply exponent rules

(2 - 2 x) ln (10) = ln (2) - x ln (10)

Solve

(2 - 2 x) ln (10) = ln (2) - x ln (10) : x = \frac{ln ( 50 )}{ln ( 10 )}

x = \frac{ln ( 50 )}{ln ( 10 )}

2^{x} + 3 \cdot 2^{x} = 64

4^{x + 5} = 4^{3 x - 2}

43 = 72 + (39 - 72) e^{k \cdot 1}

1 6^{x} = 6 4^{x + 4}

x^{- \frac{1}{700} (x)} = 94667

What is the answer to 10^{2-2x}=2*10^{-x} ?
The answer to 10^{2-2x}=2*10^{-x} is x=(ln(50))/(ln(10))
Solve for x: 10^{2-2x}=2*10^{-x}
The solution is x=(ln(50))/(ln(10))