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Popular >

43=72+(39-72)e^{k*1}

Solution

43 = 72 + (39 - 72) e^{k \cdot 1}

Solution

k = ln (\frac{29}{33})

+1

Decimal Notation

k = - 0.12921 \dots

Solution steps

43 = 72 + (39 - 72) e^{k \cdot 1}

Switch sides

72 + (39 - 72) e^{k 1} = 43

(39 - 72) e^{k 1} = - 33 e^{k 1}

72 - 33 e^{k 1} = 43

Move

72

to the right side

- 33 e^{k 1} = - 29

Divide both sides by

- 33

e^{k 1} = \frac{29}{33}

Apply exponent rules

k \cdot 1 = ln (\frac{29}{33})

Solve

k \cdot 1 = ln (\frac{29}{33}) : k = ln (\frac{29}{33})

k = ln (\frac{29}{33})

Popular Examples

1 6^{x} = 6 4^{x + 4}

x^{-1/700 (x)}=94667

x^{- \frac{1}{700} (x)} = 94667

2^{x} = 3^{x + 3}

93/151 =e^{-12k}

\frac{93}{151} = e^{- 12 k}

2^{x} = 20000000

Frequently Asked Questions (FAQ)

What is the answer to 43=72+(39-72)e^{k*1} ?
The answer to 43=72+(39-72)e^{k*1} is k=ln(29/33)