What is the answer to 6^{1-x}=9 ?

The answer to 6^{1-x}=9 is x=-(ln(3/2))/(ln(6))

Solve for x: 6^{1-x}=9

The solution is x=-(ln(3/2))/(ln(6))

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6^{1 - x} = 9

x = - \frac{ln ( \frac{3}{2} )}{ln ( 6 )}

Decimal Notation

x = - 0.22629 \dots

Solution steps

6^{1 - x} = 9

Apply exponent rules

(1 - x) ln (6) = ln (9)

Solve

(1 - x) ln (6) = ln (9) : x = - \frac{ln ( \frac{3}{2} )}{ln ( 6 )}

x = - \frac{ln ( \frac{3}{2} )}{ln ( 6 )}

3^{4 x - 7} = 5^{6 x + 11}

5^{2 x} = 8^{x - 1}

e^{2 x} + 7 e^{x} - 8 = 0

x, 2 e^{2 x} - e^{x} = 0

300 \cdot 2^{0.02 x} = 9000

What is the answer to 6^{1-x}=9 ?
The answer to 6^{1-x}=9 is x=-(ln(3/2))/(ln(6))
Solve for x: 6^{1-x}=9
The solution is x=-(ln(3/2))/(ln(6))