What is the answer to 5^{2x}=8^{x-1} ?

The answer to 5^{2x}=8^{x-1} is x=-(3ln(2))/(2ln(5)-3ln(2))

Solve for x: 5^{2x}=8^{x-1}

The solution is x=-(3ln(2))/(2ln(5)-3ln(2))

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5^{2 x} = 8^{x - 1}

x = - \frac{3 ln ( 2 )}{2 ln ( 5 ) - 3 ln ( 2 )}

Solution steps

5^{2 x} = 8^{x - 1}

Apply exponent rules

2 x ln (5) = (x - 1) ln (8)

Solve

2 x ln (5) = (x - 1) ln (8) : x = - \frac{3 ln ( 2 )}{2 ln ( 5 ) - 3 ln ( 2 )}

x = - \frac{3 ln ( 2 )}{2 ln ( 5 ) - 3 ln ( 2 )}

e^{2 x} + 7 e^{x} - 8 = 0

x, 2 e^{2 x} - e^{x} = 0

300 \cdot 2^{0.02 x} = 9000

87.88 e^{3 r} = 263.64

7 \cdot 1 0^{x} - 49 = 0

What is the answer to 5^{2x}=8^{x-1} ?
The answer to 5^{2x}=8^{x-1} is x=-(3ln(2))/(2ln(5)-3ln(2))
Solve for x: 5^{2x}=8^{x-1}
The solution is x=-(3ln(2))/(2ln(5)-3ln(2))