What is the answer to 7*10^x-49=0 ?

The answer to 7*10^x-49=0 is x=(ln(7))/(ln(10))

Solve for x: 7*10^x-49=0

The solution is x=(ln(7))/(ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 \cdot 1 0^{x} - 49 = 0

x = \frac{ln ( 7 )}{ln ( 10 )}

Decimal Notation

x = 0.84509 \dots

Solution steps

7 \cdot 1 0^{x} - 49 = 0

Add

49

to both sides

7 \cdot 1 0^{x} - 49 + 49 = 0 + 49

Simplify

7 \cdot 1 0^{x} = 49

Divide both sides by

7

1 0^{x} = 7

Apply exponent rules

x ln (10) = ln (7)

Solve

x ln (10) = ln (7) : x = \frac{ln ( 7 )}{ln ( 10 )}

x = \frac{ln ( 7 )}{ln ( 10 )}

e^{2 x} - 2 \cdot e^{x} - 3 = 0

4^{3 X - 5} = 64

2^{(\frac{t}{2})} 100 = 40000

What is the answer to 7*10^x-49=0 ?
The answer to 7*10^x-49=0 is x=(ln(7))/(ln(10))
Solve for x: 7*10^x-49=0
The solution is x=(ln(7))/(ln(10))