What is the answer to (\sqrt[3]{2})/8 =2^n ?

The answer to (\sqrt[3]{2})/8 =2^n is n=-8/3

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(\sqrt[3]{2})/8 =2^n

n = - \frac{8}{3}

Decimal Notation

n = - 2.66666 \dots

Solution steps

Apply exponent rules

- \frac{8}{3} = n

Switch sides

n = - \frac{8}{3}

2^{(\frac{t}{2})} 100 = 40000

2^{x} = - \frac{1}{4}

9^{5 x} = 2 7^{2 x - 4}

2^{x} \cdot 5^{x} = 20

4^{x + 4} = 7^{x}

What is the answer to (\sqrt[3]{2})/8 =2^n ?
The answer to (\sqrt[3]{2})/8 =2^n is n=-8/3
Solve for n: (\sqrt[3]{2})/8 =2^n
The solution is n=-8/3