What is the answer to 2^x*5^x=20 ?

The answer to 2^x*5^x=20 is x=(ln(20))/(ln(10))

Solve for x: 2^x*5^x=20

The solution is x=(ln(20))/(ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x} \cdot 5^{x} = 20

x = \frac{ln ( 20 )}{ln ( 10 )}

Decimal Notation

x = 1.30102 \dots

Solution steps

2^{x} \cdot 5^{x} = 20

Apply exponent rules

x ln (10) = ln (20)

Solve

x ln (10) = ln (20) : x = \frac{ln ( 20 )}{ln ( 10 )}

x = \frac{ln ( 20 )}{ln ( 10 )}

4^{x + 4} = 7^{x}

2^{4 x + 1} + 3 = 7 \cdot 4^{x}

x, 2 - e^{x} = 0

3 \cdot 4^{x} = 5 \cdot 7^{2 x - 2}

7^{x} = 100

What is the answer to 2^x*5^x=20 ?
The answer to 2^x*5^x=20 is x=(ln(20))/(ln(10))
Solve for x: 2^x*5^x=20
The solution is x=(ln(20))/(ln(10))