What is the answer to 3*4^x=5*7^{2x-2} ?

The answer to 3*4^x=5*7^{2x-2} is x=-(ln(147)-ln(5))/(2(ln(2)-ln(7)))

Solve for x: 3*4^x=5*7^{2x-2}

The solution is x=-(ln(147)-ln(5))/(2(ln(2)-ln(7)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 \cdot 4^{x} = 5 \cdot 7^{2 x - 2}

x = - \frac{ln ( 147 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 7 ) )}

Decimal Notation

x = 1.34941 \dots

Solution steps

3 \cdot 4^{x} = 5 \cdot 7^{2 x - 2}

Apply exponent rules

ln (3) + x ln (4) = ln (5) + (2 x - 2) ln (7)

Solve

ln (3) + x ln (4) = ln (5) + (2 x - 2) ln (7) : x = - \frac{ln ( 147 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 7 ) )}

x = - \frac{ln ( 147 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 7 ) )}

7^{x} = 100

(\frac{4}{5})^{x} = 4

3^{b} = 17

(23)^{3 x - 4} = 20736

(e^{x} + 1)^{3} e^{- x} d y = 0

What is the answer to 3*4^x=5*7^{2x-2} ?
The answer to 3*4^x=5*7^{2x-2} is x=-(ln(147)-ln(5))/(2(ln(2)-ln(7)))
Solve for x: 3*4^x=5*7^{2x-2}
The solution is x=-(ln(147)-ln(5))/(2(ln(2)-ln(7)))