What is 15-3|x+4|>8 ?

The solution to 15-3|x+4|>8 is -19/3 <x<-5/3

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15-3|x+4|>8

15 - 3 ∣ x + 4 ∣ > 8

- \frac{19}{3} < x < - \frac{5}{3}

Interval Notation

(- \frac{19}{3}, - \frac{5}{3})

Decimal Notation

- 6.33333 \dots < x < - 1.66666 \dots

Solution steps

15 - 3 ∣ x + 4 ∣ > 8

Move

15

to the right side

- 3 ∣ x + 4 ∣ > - 7

Multiply both sides by

- 1

3 ∣ x + 4 ∣ < 7

Divide both sides by

3

∣ x + 4 ∣ < \frac{7}{3}

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- \frac{7}{3} < x + 4 < \frac{7}{3}

x + 4 > - \frac{7}{3} and x + 4 < \frac{7}{3}

x > - \frac{19}{3} and x < - \frac{5}{3}

Merge Overlapping Intervals

- \frac{19}{3} < x < - \frac{5}{3}

\frac{( \frac{π}{2} )}{4}

256 - 16 t^{2} = 0

3 y + \frac{2}{5} = - \frac{1}{5}

z^{2} = 18 - 7 z

\frac{3}{2} \cdot 8