What is the answer to 50=100e^{(-(10^{10})(t))} ?

The answer to 50=100e^{(-(10^{10})(t))} is t=(ln(2))/(10^{10)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

50=100e^{(-(10^{10})(t))}

50 = 100 e^{(- (1 0^{10}) (t))}

t = \frac{ln ( 2 )}{1 0 ^{10}}

Decimal Notation

t = 6.93147 E - 11

Solution steps

50 = 100 e^{(- (1 0^{10}) (t))}

Switch sides

100 e^{- 1 0^{10} t} = 50

Divide both sides by

100

e^{- 1 0^{10} t} = \frac{1}{2}

Apply exponent rules

- 1 0^{10} t = ln (\frac{1}{2})

Solve

- 1 0^{10} t = ln (\frac{1}{2}) : t = \frac{ln ( 2 )}{1 0 ^{10}}

t = \frac{ln ( 2 )}{1 0 ^{10}}

3^{2 x + 1} + 9 = 3^{x + 3} + 3^{x}

2^{\frac{1}{x}} = 1.0168

0.8794 = 1. 3^{(- x^{2})}

2^{2 x + 7} = 3^{x - 4}

2^{n - 1} = 360000

What is the answer to 50=100e^{(-(10^{10})(t))} ?
The answer to 50=100e^{(-(10^{10})(t))} is t=(ln(2))/(10^{10)}