What is the answer to 5^x=2^{2x+1} ?

The answer to 5^x=2^{2x+1} is x=(ln(2))/(ln(5)-2ln(2))

Solve for x: 5^x=2^{2x+1}

The solution is x=(ln(2))/(ln(5)-2ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{x} = 2^{2 x + 1}

x = \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

Decimal Notation

x = 3.10628 \dots

Solution steps

5^{x} = 2^{2 x + 1}

Apply exponent rules

x ln (5) = (2 x + 1) ln (2)

Solve

x ln (5) = (2 x + 1) ln (2) : x = \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

x = \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

2 9^{9 x - 4} = 125

t, N = a e^{- 0.21 \cdot t}

21 6^{- 3 x} = 36

5^{6 - x} = 1

50 e^{- 0.12 t} = 10

What is the answer to 5^x=2^{2x+1} ?
The answer to 5^x=2^{2x+1} is x=(ln(2))/(ln(5)-2ln(2))
Solve for x: 5^x=2^{2x+1}
The solution is x=(ln(2))/(ln(5)-2ln(2))