What is the answer to 67*3^{2x}=536 ?

The answer to 67*3^{2x}=536 is x=(3ln(2))/(2ln(3))

Solve for x: 67*3^{2x}=536

The solution is x=(3ln(2))/(2ln(3))

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67 \cdot 3^{2 x} = 536

x = \frac{3 ln ( 2 )}{2 ln ( 3 )}

Decimal Notation

x = 0.94639 \dots

Solution steps

67 \cdot 3^{2 x} = 536

Divide both sides by

67

3^{2 x} = 8

Apply exponent rules

2 x ln (3) = ln (8)

Solve

2 x ln (3) = ln (8) : x = \frac{3 ln ( 2 )}{2 ln ( 3 )}

x = \frac{3 ln ( 2 )}{2 ln ( 3 )}

9^{x} = (\frac{1}{9})^{x + 3}

(\frac{6}{5})^{n} = 16

4^{2 x - 3} = 1

z, e^{2 x + 2 y + z} = c

8^{x - 2} = 1 6^{5 x + 4}

What is the answer to 67*3^{2x}=536 ?
The answer to 67*3^{2x}=536 is x=(3ln(2))/(2ln(3))
Solve for x: 67*3^{2x}=536
The solution is x=(3ln(2))/(2ln(3))