What is the answer to 6^{x-1}=7 ?

The answer to 6^{x-1}=7 is x=(ln(7))/(ln(6))+1

Solve for x: 6^{x-1}=7

The solution is x=(ln(7))/(ln(6))+1

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6^{x - 1} = 7

x = \frac{ln ( 7 )}{ln ( 6 )} + 1

Decimal Notation

x = 2.08603 \dots

Solution steps

6^{x - 1} = 7

Apply exponent rules

(x - 1) ln (6) = ln (7)

Solve

(x - 1) ln (6) = ln (7) : x = \frac{ln ( 7 )}{ln ( 6 )} + 1

x = \frac{ln ( 7 )}{ln ( 6 )} + 1

3^{(2 x + 1)} = 7^{(x + 1)}

\frac{1}{e ^{- x}} = e^{x}

x 5^{2 x + 3} = \frac{1}{25}

8200 = 6400 \cdot (1.054)^{4 x}

e^{4 x} - 7 e^{2 x} + 12 = 0

What is the answer to 6^{x-1}=7 ?
The answer to 6^{x-1}=7 is x=(ln(7))/(ln(6))+1
Solve for x: 6^{x-1}=7
The solution is x=(ln(7))/(ln(6))+1