What is the answer to 2^{(x-3)/(2x-1)}=sqrt(8) ?

The answer to 2^{(x-3)/(2x-1)}=sqrt(8) is x=-3/4

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2^{(x-3)/(2x-1)}=sqrt(8)

2^{\frac{x - 3}{2 x - 1}} = 8

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

2^{\frac{x - 3}{2 x - 1}} = 8

Apply exponent rules

\frac{x - 3}{2 x - 1} = \frac{3}{2}

Solve

\frac{x - 3}{2 x - 1} = \frac{3}{2} : x = - \frac{3}{4}

x = - \frac{3}{4}

b, c = a^{b}

\frac{6}{e ^{x}} - 5 = e^{x}

4 \cdot 3^{7 x} = 9 \cdot 2^{7 x}

3^{3 μ} = \frac{1}{27} 3

What is the answer to 2^{(x-3)/(2x-1)}=sqrt(8) ?
The answer to 2^{(x-3)/(2x-1)}=sqrt(8) is x=-3/4
Solve for x: 2^{(x-3)/(2x-1)}=sqrt(8)
The solution is x=-3/4