What is the answer to 7^{(3x+7)}=7^{(-8x-4)} ?

The answer to 7^{(3x+7)}=7^{(-8x-4)} is x=-1

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7^{(3x+7)}=7^{(-8x-4)}

7^{(3 x + 7)} = 7^{(- 8 x - 4)}

x = - 1

Solution steps

7^{(3 x + 7)} = 7^{(- 8 x - 4)}

Apply exponent rules

3 x + 7 = - 8 x - 4

Solve

3 x + 7 = - 8 x - 4 : x = - 1

x = - 1

40 = 100 \cdot 1 0^{- k^{5}}

x, 3^{2 x} - 2^{2 y} - 713 = 0

x, 9^{x} - 2 (3^{x}) - 15 = 0

4^{x - 1} \cdot 5^{2 x + 3} = 6

3^{7 x + 1} = 6561

What is the answer to 7^{(3x+7)}=7^{(-8x-4)} ?
The answer to 7^{(3x+7)}=7^{(-8x-4)} is x=-1
Solve for x: 7^{(3x+7)}=7^{(-8x-4)}
The solution is x=-1