What is the answer to 4^{y-2}=3^y ?

The answer to 4^{y-2}=3^y is y=(4ln(2))/(2ln(2)-ln(3))

Solve for y: 4^{y-2}=3^y

The solution is y=(4ln(2))/(2ln(2)-ln(3))

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4^{y - 2} = 3^{y}

y = \frac{4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

y = 9.63768 \dots

Solution steps

4^{y - 2} = 3^{y}

Apply exponent rules

(y - 2) ln (4) = y ln (3)

Solve

(y - 2) ln (4) = y ln (3) : y = \frac{4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

y = \frac{4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

2^{x} = 3^{1 - x}

5 = 10 e^{- 0.008 (x)}

3^{x} - 3^{x - 2} = a \cdot 3^{x}

e^{2 b} = b + 3

500000 = - 3 e^{- 5 x} + 35.156

What is the answer to 4^{y-2}=3^y ?
The answer to 4^{y-2}=3^y is y=(4ln(2))/(2ln(2)-ln(3))
Solve for y: 4^{y-2}=3^y
The solution is y=(4ln(2))/(2ln(2)-ln(3))