What is the answer to 2^{p+3}=67 ?

The answer to 2^{p+3}=67 is p=(ln(67))/(ln(2))-3

Solve for p: 2^{p+3}=67

The solution is p=(ln(67))/(ln(2))-3

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2^{p + 3} = 67

p = \frac{ln ( 67 )}{ln ( 2 )} - 3

Decimal Notation

p = 3.06608 \dots

Solution steps

2^{p + 3} = 67

Apply exponent rules

(p + 3) ln (2) = ln (67)

Solve

(p + 3) ln (2) = ln (67) : p = \frac{ln ( 67 )}{ln ( 2 )} - 3

p = \frac{ln ( 67 )}{ln ( 2 )} - 3

6^{n} - 9 = 0

y, x e^{y} + y e^{x} = 3

4^{x + 1} = 8^{2 x + 3}

(1000) 1.0 5^{3 x} = 3000

4 9^{x} = 21

What is the answer to 2^{p+3}=67 ?
The answer to 2^{p+3}=67 is p=(ln(67))/(ln(2))-3
Solve for p: 2^{p+3}=67
The solution is p=(ln(67))/(ln(2))-3