What is ((x^4y^2)/(z^{-4)})^{-3} ?

The solution to ((x^4y^2)/(z^{-4)})^{-3} is 1/(x^{12)y^6z^{12}}

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simplify ((x^4y^2)/(z^{-4)})^{-3}

simplify

(\frac{x ^{4} y ^{2}}{z ^{- 4}})^{- 3}

\frac{1}{x ^{12} y ^{6} z ^{12}}

Solution steps

(\frac{x ^{4} y ^{2}}{z ^{- 4}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{4} y ^{2}}{z ^{- 4}})^{- 3} = \frac{1}{( \frac{x ^{4} y ^{2}}{z ^{- 4}} ) ^{3}}

= \frac{1}{( \frac{x ^{4} y ^{2}}{z ^{- 4}} ) ^{3}}

Simplify

(\frac{x ^{4} y ^{2}}{z ^{- 4}})^{3} : x^{12} y^{6} z^{12}

= \frac{1}{x ^{12} y ^{6} z ^{12}}

\frac{x + 3}{2} = \frac{3 x + 5}{5}

\frac{m ^{2} p q ^{- 1}}{4 m ^{- 2} p q ^{3}}

1 + tan^{2} (x)

- 12 x = 3 x^{2} + 9

12 x^{2} + 8 x = 0

What is ((x^4y^2)/(z^{-4)})^{-3} ?
The solution to ((x^4y^2)/(z^{-4)})^{-3} is 1/(x^{12)y^6z^{12}}