What are the solutions to the equation 12x^2+8x=0 ?

The solutions to the equation 12x^2+8x=0 are x=0,x=-2/3

Find the zeros of 12x^2+8x=0

The zeros of 12x^2+8x=0 are x=0,x=-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} + 8 x = 0

x = 0, x = - \frac{2}{3}

Decimal Notation

x = 0, x = - 0.66666 \dots

Solution steps

12 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

8^{2} - 4 \cdot 12 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 12}, x_{2} = \frac{- 8 - 8}{2 \cdot 12}

x = \frac{- 8 + 8}{2 \cdot 12} : 0

x = \frac{- 8 - 8}{2 \cdot 12} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{2}{3}

\frac{1}{9} + \frac{1}{3}

\frac{y}{2} < 3

5 w^{2} - 46 w + 9 = 0

3 - 5 x > - 2

ln (- 3)

What are the solutions to the equation 12x^2+8x=0 ?
The solutions to the equation 12x^2+8x=0 are x=0,x=-2/3
Find the zeros of 12x^2+8x=0
The zeros of 12x^2+8x=0 are x=0,x=-2/3