What is the answer to 98415/8 =8*3^{n-1} ?

The answer to 98415/8 =8*3^{n-1} is n=(ln(98415/64))/(ln(3))+1

Solve for n: 98415/8 =8*3^{n-1}

The solution is n=(ln(98415/64))/(ln(3))+1

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\frac{98415}{8} = 8 \cdot 3^{n - 1}

n = \frac{ln ( \frac{98415}{64} )}{ln ( 3 )} + 1

Decimal Notation

n = 7.67939 \dots

Solution steps

\frac{98415}{8} = 8 \cdot 3^{n - 1}

Switch sides

8 \cdot 3^{n - 1} = \frac{98415}{8}

Divide both sides by

8

3^{n - 1} = \frac{98415}{64}

Apply exponent rules

(n - 1) ln (3) = ln (\frac{98415}{64})

Solve

(n - 1) ln (3) = ln (\frac{98415}{64}) : n = \frac{ln ( \frac{98415}{64} )}{ln ( 3 )} + 1

n = \frac{ln ( \frac{98415}{64} )}{ln ( 3 )} + 1

e^{x} = 7.1

e^{x} = 7.9

8^{4 x} = 5^{x - 9}

- 10 \cdot 8^{- 5 n} = - 81

8^{x - 1} = 4^{x + 1}

What is the answer to 98415/8 =8*3^{n-1} ?
The answer to 98415/8 =8*3^{n-1} is n=(ln(98415/64))/(ln(3))+1
Solve for n: 98415/8 =8*3^{n-1}
The solution is n=(ln(98415/64))/(ln(3))+1