What is the answer to 7^{2x}=2*(5^{3x+1}) ?

The answer to 7^{2x}=2*(5^{3x+1}) is x=(ln(10))/(2ln(7)-3ln(5))

Solve for x: 7^{2x}=2*(5^{3x+1})

The solution is x=(ln(10))/(2ln(7)-3ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{2 x} = 2 \cdot (5^{3 x + 1})

x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 5 )}

Decimal Notation

x = - 2.45873 \dots

Solution steps

7^{2 x} = 2 (5^{3 x + 1})

Apply exponent rules

2 x ln (7) = ln (2) + (3 x + 1) ln (5)

Solve

2 x ln (7) = ln (2) + (3 x + 1) ln (5) : x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 5 )}

x = \frac{ln ( 10 )}{2 ln ( 7 ) - 3 ln ( 5 )}

8^{x} = 2^{x + 6}

q, c = 1 0^{0 q + 2} + 50

4^{2 + m} = 4^{4 + 3 m}

x, x - e^{- x} = 0

57 = 1 1^{x}

What is the answer to 7^{2x}=2*(5^{3x+1}) ?
The answer to 7^{2x}=2*(5^{3x+1}) is x=(ln(10))/(2ln(7)-3ln(5))
Solve for x: 7^{2x}=2*(5^{3x+1})
The solution is x=(ln(10))/(2ln(7)-3ln(5))