What is the answer to 2^{-x-7}=11^{2x} ?

The answer to 2^{-x-7}=11^{2x} is x=-(7ln(2))/(ln(242))

Solve for x: 2^{-x-7}=11^{2x}

The solution is x=-(7ln(2))/(ln(242))

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2^{- x - 7} = 1 1^{2 x}

x = - \frac{7 ln ( 2 )}{ln ( 242 )}

Decimal Notation

x = - 0.88396 \dots

Solution steps

2^{- x - 7} = 1 1^{2 x}

Apply exponent rules

(- x - 7) ln (2) = 2 x ln (11)

Solve

(- x - 7) ln (2) = 2 x ln (11) : x = - \frac{7 ln ( 2 )}{ln ( 242 )}

x = - \frac{7 ln ( 2 )}{ln ( 242 )}

1 6^{x + 4} = 6 4^{4 x - 2}

5^{3 x + 2} = 25

2^{x - 1} = 2^{2 x + 8}

5^{2 x + 1} - 26 \cdot 5^{x} + 5 = 0

y = x e^{0.055 x}

What is the answer to 2^{-x-7}=11^{2x} ?
The answer to 2^{-x-7}=11^{2x} is x=-(7ln(2))/(ln(242))
Solve for x: 2^{-x-7}=11^{2x}
The solution is x=-(7ln(2))/(ln(242))