What is the answer to 5^{2x+1}-26*5^x+5=0 ?

The answer to 5^{2x+1}-26*5^x+5=0 is x=1,x=-1

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5^{2x+1}-26*5^x+5=0

5^{2 x + 1} - 26 \cdot 5^{x} + 5 = 0

x = 1, x = - 1

Solution steps

5^{2 x + 1} - 26 \cdot 5^{x} + 5 = 0

Apply exponent rules

(5^{x})^{2} \cdot 5^{1} - 26 \cdot 5^{x} + 5 = 0

Rewrite the equation with

5^{x} = u

(u)^{2} \cdot 5^{1} - 26 u + 5 = 0

Solve

u^{2} \cdot 5^{1} - 26 u + 5 = 0 : u = 5, u = \frac{1}{5}

u = 5, u = \frac{1}{5}

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 5 : x = 1

Solve

5^{x} = \frac{1}{5} : x = - 1

x = 1, x = - 1

y = x e^{0.055 x}

e^{3 x - 1} = 100

\frac{5}{3} = e^{3 k}

2 = e^{k^{34}}

3^{2 x + 1} = 5^{3 x - 1}

What is the answer to 5^{2x+1}-26*5^x+5=0 ?
The answer to 5^{2x+1}-26*5^x+5=0 is x=1,x=-1
Solve for x: 5^{2x+1}-26*5^x+5=0
The solution is x=1,x=-1