What is the answer to 3^{2x+1}=5^{3x-1} ?

The answer to 3^{2x+1}=5^{3x-1} is x=(ln(15))/(3ln(5)-2ln(3))

Solve for x: 3^{2x+1}=5^{3x-1}

The solution is x=(ln(15))/(3ln(5)-2ln(3))

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3^{2 x + 1} = 5^{3 x - 1}

x = \frac{ln ( 15 )}{3 ln ( 5 ) - 2 ln ( 3 )}

Decimal Notation

x = 1.02925 \dots

Solution steps

3^{2 x + 1} = 5^{3 x - 1}

Apply exponent rules

(2 x + 1) ln (3) = (3 x - 1) ln (5)

Solve

(2 x + 1) ln (3) = (3 x - 1) ln (5) : x = \frac{ln ( 15 )}{3 ln ( 5 ) - 2 ln ( 3 )}

x = \frac{ln ( 15 )}{3 ln ( 5 ) - 2 ln ( 3 )}

\frac{200}{335} = e^{15 x}

4^{x} 3^{x + 1} = 1 2^{2 x - 1}

(4^{x})^{2} - 3 = 5

6640 = 5000 (1 + 0.001)^{T}

3^{(- 2)} \cdot 3^{(2 x)} = 7

What is the answer to 3^{2x+1}=5^{3x-1} ?
The answer to 3^{2x+1}=5^{3x-1} is x=(ln(15))/(3ln(5)-2ln(3))
Solve for x: 3^{2x+1}=5^{3x-1}
The solution is x=(ln(15))/(3ln(5)-2ln(3))