What is the answer to 18(2^x)=2+2^{x+1} ?

The answer to 18(2^x)=2+2^{x+1} is x=-3

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18(2^x)=2+2^{x+1}

18 (2^{x}) = 2 + 2^{x + 1}

x = - 3

Solution steps

18 (2^{x}) = 2 + 2^{x + 1}

Subtract

2^{x + 1}

from both sides

18 \cdot 2^{x} - 2^{x + 1} = 2 + 2^{x + 1} - 2^{x + 1}

Simplify

18 \cdot 2^{x} - 2^{x + 1} = 2

Factor

18 \cdot 2^{x} - 2^{x + 1} : 2^{4 + x}

2^{4 + x} = 2

Apply exponent rules

4 + x = 1

Solve

4 + x = 1 : x = - 3

x = - 3

1 6^{3 x - 6} = 6 4^{x + 3}

2 e^{2 x} + 5 e^{x} = 3

7^{2 x} = 1 0^{3 x + 1}

x, 9^{x} = 243

1 6^{\frac{2}{x}} = 2

What is the answer to 18(2^x)=2+2^{x+1} ?
The answer to 18(2^x)=2+2^{x+1} is x=-3
Solve for x: 18(2^x)=2+2^{x+1}
The solution is x=-3