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Popular >

2^{2x-1}=16

Solution

2^{2 x - 1} = 16

Solution

x = \frac{5}{2}

+1

Decimal Notation

x = 2.5

Solution steps

2^{2 x - 1} = 16

Apply exponent rules

2 x - 1 = 4

Solve

2 x - 1 = 4 : x = \frac{5}{2}

x = \frac{5}{2}

Popular Examples

x^{-3+log_{3}(x)}=81

x^{- 3 + l o g_{3} (x)} = 81

12 = 7^{x}

3^{2x}-30*3^x+81=0

3^{2 x} - 30 \cdot 3^{x} + 81 = 0

(5x+11)^{2x-1}=(5x+11)^{x-6}

(5 x + 11)^{2 x - 1} = (5 x + 11)^{x - 6}

2^{2x}-5(2^x)+6=0

2^{2 x} - 5 (2^{x}) + 6 = 0

Frequently Asked Questions (FAQ)

What is the answer to 2^{2x-1}=16 ?
The answer to 2^{2x-1}=16 is x= 5/2
Solve for x: 2^{2x-1}=16
The solution is x= 5/2