What is the answer to 3^{2x+1}=27^{x+2} ?

The answer to 3^{2x+1}=27^{x+2} is x=-5

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3^{2x+1}=27^{x+2}

3^{2 x + 1} = 2 7^{x + 2}

x = - 5

Solution steps

3^{2 x + 1} = 2 7^{x + 2}

Apply exponent rules

2 x + 1 = 3 (x + 2)

Solve

2 x + 1 = 3 (x + 2) : x = - 5

x = - 5

(\frac{1}{9})^{x - 5} = 27

5 = 1 5^{2 - 0.01 q}

x, 2 e^{x} + 5 = 3 e^{- x}

e^{x} - 6 e^{x} - 1 = 0

0 = 3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6)

What is the answer to 3^{2x+1}=27^{x+2} ?
The answer to 3^{2x+1}=27^{x+2} is x=-5
Solve for x: 3^{2x+1}=27^{x+2}
The solution is x=-5