What is the answer to 2^{x+2}-(6)(2)^{x-1}-8=0 ?

The answer to 2^{x+2}-(6)(2)^{x-1}-8=0 is x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+2}-(6)(2)^{x-1}-8=0

2^{x + 2} - (6) (2)^{x - 1} - 8 = 0

x = 3

Solution steps

2^{x + 2} - (6) (2)^{x - 1} - 8 = 0

Factor

2^{x + 2} - 6 \cdot 2^{x - 1} - 8 : 2^{x} - 8

2^{x} - 8 = 0

Add

8

to both sides

2^{x} - 8 + 8 = 0 + 8

Simplify

2^{x} = 8

Apply exponent rules

x = 3

(2 x + 4)^{5 - x} = (2 x + 4)^{3 - 2 x}

e^{x} = 0.4

e^{l n (3 x)} = 11

40000 = 2^{t} \cdot 100

2 e^{4 x} + 7 = 12

What is the answer to 2^{x+2}-(6)(2)^{x-1}-8=0 ?
The answer to 2^{x+2}-(6)(2)^{x-1}-8=0 is x=3
Solve for x: 2^{x+2}-(6)(2)^{x-1}-8=0
The solution is x=3