What is the answer to 3^{2+x}=5^x ?

The answer to 3^{2+x}=5^x is x=(2ln(3))/(ln(5)-ln(3))

Solve for x: 3^{2+x}=5^x

The solution is x=(2ln(3))/(ln(5)-ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2 + x} = 5^{x}

x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 4.30132 \dots

Solution steps

3^{2 + x} = 5^{x}

Apply exponent rules

(2 + x) ln (3) = x ln (5)

Solve

(2 + x) ln (3) = x ln (5) : x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{2 ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

3^{2 x - 7} = 9

2 4^{- \frac{1}{x}} = \frac{1}{8}

(2)^{x} = 4^{x + 2}

lo g_{2} (2^{x + 1}) = 4

2 7^{5} = 3^{4 m + 3}

What is the answer to 3^{2+x}=5^x ?
The answer to 3^{2+x}=5^x is x=(2ln(3))/(ln(5)-ln(3))
Solve for x: 3^{2+x}=5^x
The solution is x=(2ln(3))/(ln(5)-ln(3))